Handling left over carriage return

Lines in text files created in Windows end with '\r\n'. If you read that text file in Linux with C++ getline(), your line will have a '\r' at the end because in Linux, getline() only gets rid of '\n'. If you have code that reads a certain number of characters and converts it to floating point using std::stod(), you might get std::invalid_argument exception when trying to read multiple values. You can use the following to take care of this problem:

	//blog post: https://simulinkforsoftwareengineers.blogspot.com/2023/11/handling-left-over-carriage-return.html
	#include <iostream>
	#include <string>
	bool isCarriageReturn(const char c) {
	return c == '\r';
	}
	int main() {
	std::string line = "\r1.2\r4.56";
	const uint32_t wordSize = 4; //length of characters in number
	for (size_t i = 0; i < line.length(); i += wordSize) {
	std::string word = line.substr(i, wordSize);
	//std::cout << "Word: " << word;
	//Text files created in Windows have line endings of '\r\n'. On Linux, getline() reads up to '\n' which leaves and extra '\r' at the end of line:
	if (isCarriageReturn(word.front())) {
	//std::cout << "*** here 1\n";
	i++;
	word = line.substr(i, wordSize);
	}
	if (isCarriageReturn(word.back())) {
	//std::cout << "*** here 2\n";
	word.pop_back();
	}
	double number = std::stod(word);
	std::cout << "number: " << number << std::endl;
	}
	return 0;
	}

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